##########################
### Function for replacing ^ to pow
### 15.11.2016-18.11.2016
### A.Kalinkin
#########################
replacePow <- function(e) {
#check if you are at the end of the tree's branch
#e - string as expression(using parse function)
if (is.name(e) || is.atomic(e)) {
#replace ^
if (e == quote(`^`)) return(quote(pow))
return(e)
}
if (e[[1]] == quote(sqrt)) {
#replace sqrt
e[[1]] <- quote(pow)
#add the second argument
e[[3]] <- quote(0.5)
}
#follow the tree with recursion
for (i in seq_along(e)) e[[i]] <- replacePow(e[[i]])
return(e)
}
print_parsed <- function(e) {
deparse(replacePow(e)[[1]])
}
parsed <- function(t) {
e=parse(text=t)
return(e)
}
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