# check vs. CBP 1967 table 1
Tt_r2 <- rep(c(1.0, 2.15, 4.64), 4) * 10^(rep(c(-3, -2, -1, 0), each = 3))
a_01 <- c(0.9771, 0.9658, 0.9490, 0.9238, 0.8860, 0.8283,
0.7460, 0.6289, 0.4782, 0.3117, 0.1665, 0.07415)
a_0001 <- c(0.9969, 0.9949, 0.9914, 0.9853, 0.9744, 0.9545,
0.9183, 0.8538, 0.7436, 0.5729, 0.3543, 0.1554)
a_000001 <- c(0.9992, 0.9985, 0.9970, 0.9942, 0.9888, 0.9781,
0.9572, 0.9167, 0.8410, 0.7080, 0.5038, 0.2620)
dat <- list(x = Tt_r2)
formula = formula(x~.)
#^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
frec1 = recipe(formula = formula, data = dat) |>
step_slug_cbp(
times = x,
radius = 1.0,
radius_casing = 1.0,
radius_well = 1.0,
specific_storage = 1e-1,
hydraulic_conductivity = 1.0,
thickness = 1.0,
head_0 = 1.0,
n_terms = 12L
) |>
plate("dt")
expect_equivalent(frec1[[2]], a_01, tolerance = 1e-3,
info = "R6 and hydrorecipes api are equivalent")
frec1 = recipe(formula = formula, data = dat) |>
step_slug_cbp(
times = x,
radius = 1.0,
radius_casing = 1.0,
radius_well = 1.0,
specific_storage = 1e-3,
hydraulic_conductivity = 1.0,
thickness = 1.0,
head_0 = 1.0,
n_terms = 12L
) |>
plate("dt")
expect_equivalent(frec1[[2]], a_0001, tolerance = 1e-3,
info = "R6 and hydrorecipes api are equivalent")
frec1 = recipe(formula = formula, data = dat) |>
step_slug_cbp(
times = x,
radius = 1.0,
radius_casing = 1.0,
radius_well = 1.0,
specific_storage = 1e-5,
hydraulic_conductivity = 1.0,
thickness = 1.0,
head_0 = 1.0,
n_terms = 12L
) |>
plate("dt")
expect_equivalent(frec1[[2]], a_000001, tolerance = 1e-3,
info = "R6 and hydrorecipes api are equivalent")
dat <- list(x = 0.0)
h_0 <- 20
frec1 = recipe(formula = formula, data = dat) |>
step_slug_cbp(
times = x,
radius = 1.0,
radius_casing = 1.0,
radius_well = 1.0,
specific_storage = 1e-5,
hydraulic_conductivity = 1.0,
thickness = 1.0,
head_0 = h_0,
n_terms = 12L
) |>
plate("dt")
expect_equivalent(frec1[[2]], h_0,
info = "R6 and hydrorecipes api are equivalent")
# time = c(0, 1:86400)
#
# kern_slug <- hydrorecipes:::cooper_bredehoeft_papadopulos_laplace(time,
# r = 0.10,
# r_c = 0.10,
# r_w = 0.10,
# S = 1e-5,
# Tr = 5e-4,
# h_0 = 1,
# n = 14L)
#
# dat <- data.table(x = time)
# frec1 = recipe(formula = formula, data = dat) |>
# step_slug_cbp(
# times = x,
# radius = 0.1,
# radius_casing = 0.1,
# radius_well = 0.1,
# specific_storage = 1e-5,
# hydraulic_conductivity = 5e-4,
# thickness = 1.0,
# head_0 = 1.0,
# n_terms = 14L
# ) |>
# plate("dt")
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