EmpPerc_Peso <- function(items, responses,vecform,profi,resp_possible,nitems,nitemform,nforms,min_break,max_break,by_break,escala0100=F,peso = NULL)
{
if(is.null(peso)) peso <- rep(1,length(responses))
(cut_break <- c(-Inf,seq((min_break+by_break/2),(max_break-by_break/2),by_break),Inf))
(if(escala0100==T) cut_break <- c(-Inf,0.1,cut_break[-c(1:2,length(cut_break)-1,length(cut_break))],99.9,Inf))
(exib_break <- seq((min_break) , (max_break), by_break))
(if(escala0100==T) exib_break <- c(0,exib_break[-c(1,length(exib_break))],100))
it_level <- (cut(profi,cut_break,labels = exib_break,include.lowest=T,right=F))
#as.matrix(table(vecform,cut(profi,cut_break,labels = exib_break,include.lowest = TRUE, right = FALSE)))
### criando matriz de respostas
resp_matrix <- data.frame(do.call(rbind,strsplit(responses,NULL)),stringsAsFactors=F)
for(i in 1:nitemform){
resp_matrix[,i] <- factor(resp_matrix[,i],levels=resp_possible)
}
#n?mero total de respondentes
nalu <- length(responses)
#n?mero de alternativas (incluindo branco/inv?lido e n?o-apresentado)
nalt <- length(resp_possible)
itempos <- ItemPos(items,nitems,tipo='character')
EmpPerc <- list()
EmpPerc[[1]] <- list()
EmpPerc[[2]] <- list()
writeLines("\n Calculando os percentuais emp?ricos...")
for(i in 1:nitems){
setTxtProgressBar(txtProgressBar(min=1,max=nitems,style=3,width=70,initial=1),i)
(df_empperc <- data.frame(matrix(NA,ncol=3,nrow=nalu)))
(df_empperc[,1] <- factor(df_empperc[,1],levels=exib_break))
(df_empperc[,2] <- factor(df_empperc[,2],levels=resp_possible))
(df_empperc[,3] <- peso)
(nlin <- nrow(itempos[[i]]))
for(j in 1:nlin){
(form = itempos[[i]][j,'form'])
(pos = as.numeric(itempos[[i]][j,'pos']))
(aux <- vecform==form)
(df_empperc[aux,1] <- it_level[aux])
(df_empperc[aux,2] <- resp_matrix[aux,pos])
}
#(df_empperc <- df_empperc[df_empperc[,1]!='0',])
tempaux <- tapply(df_empperc[,3], list(df_empperc[,2],df_empperc[,1]), sum, na.rm = TRUE)
tempaux[is.na(tempaux)] <- 0
(EmpPerc[[1]][[i]] <- tempaux)
EmpPerc[[2]][[i]] <- EmpPerc[[1]][[i]]
for(k in 1: nrow(EmpPerc[[1]][[i]])){
EmpPerc[[2]][[i]][k,] <- EmpPerc[[1]][[i]][k,]/colSums(EmpPerc[[1]][[i]])
EmpPerc[[2]][[i]][,colSums(EmpPerc[[1]][[i]])==0] <- 0
}
}
EmpPerc
}
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