belong9: indicates inclusion of character string

In rbsa: Ancillary Functions for R Programming

Description

Checks if some string(s) belong(s) to a series of strings. When exact is FALSE, returns TRUE if the character string sch is included at least once into the character string ch.
sch can be a vector, in that case, the check is made for each of its components. According to how the returned value is vectorial or scalar. When sch is zero length then TRUE is returned. When ch is zero length then FALSE is returned except when length(sch) is zero.

Usage

 
  belong9(sch,ch,exact=FALSE,how="a",lower=FALSE,
          monitor=rbsa0$monitor$v) 

Arguments

sch	The character string(s) to be found.
ch	The character string(s) to investigate.
exact	When exact, one component must be strictly identical, if not a subtring is sufficient. See also the Details section for two other possibilities.
how	Indicates what to do when length(sch)>1. The choice are v: a logical vector gives back each check independently; 1: returns TRUE when at least one of the component belongs to the series ch and a when all components must comply to get TRUE.
lower	Must the comparisons being done after case lowering?
monitor	List of constants indicating the monitoring choices, see the rbsa0$monitor$v provided object as an example.

Details

More possibilities exists when exact is 6 or 8. Namely that the substring must be at the end or at the beginning of the reference chain.

Value

A logical vector with length of sch; or TRUE or FALSE when how is 1 or a.

Examples

 
  belong9('a','non'); 
  belong9('o',c('non','oui')); 
  belong9('o',c('non','oui'),6); 
  belong9('o',c('non','oui'),8); 
  belong9('O',c("oui")); 
  belong9('O',c("oui"),lower=TRUE); 
  belong9(c('o','n'),c('non','oui'),6,how='v'); 
  belong9(c('o','n'),c('non','oui'),8,how='v'); 
  belong9(c("o","oui"),c('non','oui')); 
  belong9(c("o","oui"),c('non','oui'),how="v"); 
  belong9(c("A[SEX]","A[AGE]"),c("A[AGE]","A[SEX]"),how="a") 

rbsa documentation built on May 2, 2019, 6:07 p.m.