invyrfraction: Inverse fraction of the year

In season: Seasonal analysis of health data

Description

Inverts a fraction of the year to a date variable or month fraction.

Usage

invyrfraction(frac, type="daily", text=TRUE)

Arguments

frac	a vector of fractions of the year, all between 0 and 1.
type	“daily” for dates, or “monthly” for months.
text	add an explanatory text to the returned value (TRUE) or return a number (FALSE).

Details

Returns the day and month (for daily) or fraction of the month (for monthly) given a fraction of the year. Assumes a year length of 365.25 days for daily. When using monthly the 1st of January is 1, the 1st of December is 12, and the 31st of December is 12.9.

Value

daym	date (day and month for daily) or fractional month (for monthly).

Author(s)

Adrian Barnett a.barnett<at>qut.edu.au

Examples

invyrfraction(c(0,0.5,0.99), type='daily')
invyrfraction(c(0,0.5,0.99), type='monthly')

season documentation built on May 2, 2019, 5:22 p.m.