Description Usage Format Source References Examples
This dataset gives the actual and motor imaginary performances (time) in horse-riding for 8 beginners.
1 |
A dataframe with 8 rows and 3 columns.
[,1] | Subject | factor | Anonymous subjects |
[,2] | Actual | numeric | Actual performance (sec.) |
[,3] | Imaginary | numeric | Imaginary performance (sec.) |
Private communication. Aymeric Guillot, CRIS, Lyon 1 University, FRANCE.
Louis, M. Collet, C. Champely, S. and Guillot, A. (2010) Differences in motor imagery time when predicting task duration. Research Quarterly for Exercise and Sport.
1 2 3 4 5 6 7 8 9 10 11 | data(HorseBeginners)
# There is one outlier
with(HorseBeginners,plot(paired(Actual,Imaginary),type="profile"))
# This outlier has a great influence
# on the non robust Pitman-Morgan test of variances
with(HorseBeginners,Var.test(paired(Actual,Imaginary)))
with(HorseBeginners[-1,],Var.test(paired(Actual,Imaginary)))
with(HorseBeginners,grambsch.Var.test(paired(Actual,Imaginary)))
with(HorseBeginners,bonettseier.Var.test(paired(Actual,Imaginary)))
|
Loading required package: MASS
Loading required package: gld
Loading required package: mvtnorm
Loading required package: lattice
Loading required package: ggplot2
Attaching package: 'PairedData'
The following object is masked from 'package:base':
summary
Paired Pitman-Morgan test
data: Actual and Imaginary
t = -3.2675, df = 6, p-value = 0.01709
alternative hypothesis: true ratio of variances is not equal to 1
95 percent confidence interval:
0.01975295 0.64755197
sample estimates:
variance of x variance of y
41.55964 367.46713
Paired Pitman-Morgan test
data: Actual and Imaginary
t = -1.3054, df = 5, p-value = 0.2486
alternative hypothesis: true ratio of variances is not equal to 1
95 percent confidence interval:
0.05133341 2.30538289
sample estimates:
variance of x variance of y
48.4735 140.9071
Paired Grambsch test
data: Actual and Imaginary
z = -1.5391, p-value = 0.1238
alternative hypothesis: true ratio of variances is not equal to 1
Paired Bonett-Seier test
data: Actual and Imaginary
z = -1.6579, p-value = 0.09734
alternative hypothesis: true ratio of means absolute deviations is not equal to 1
95 percent confidence interval:
0.1044491 1.2075867
sample estimates:
mean abs. dev. of x mean abs. dev. of y
4.78875 13.48375
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