Nothing
nptl <-
function(n,p=0.95,gam=0.95){
# function nptl(n,p,gam)
# For a random sample of size n calculate largest value
# of m such that with confidence level gamma
# 100p percent of population lies below the
# mth largest data value in the sample... see Section 3.6
# USAGE: nptl(n,p,gam)
# ARGUMENTS: n: sample size p: defined above
# gam: confidence level for one-sided interva
# VALUE: m
# DETAILS: Requries R function qbeata(p,par1,par2)
# REFERENCES:
# Sommerville, P.N. (1958) Annals Math Stat pp 599-601
k <- ceiling(n*p)
pv <- qbeta(1-gam,k,n+1-k)
while( pv < p && k < n+1){
k <- k + 1
if( k == n + 1) next
pv<-qbeta(1-gam,k,n+1-k)
}
if( k <= n) m<- n+1-k else m<- NA
m
}
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