oipospoisUC: One-Inflated Positive Poisson Distribution

OipospoisR Documentation

One-Inflated Positive Poisson Distribution


Density, distribution function, quantile function and random generation for the one-inflated positive Poisson distribution with parameter pstr1.


doipospois(x, lambda, pstr1 = 0, log = FALSE)
poipospois(q, lambda, pstr1 = 0)
qoipospois(p, lambda, pstr1 = 0)
roipospois(n, lambda, pstr1 = 0)


x, p, q, n

Same as Pospois.


Vector of positive means.


Probability of a structural one (i.e., ignoring the positive Poisson distribution), called phi. The default value of phi = 0 corresponds to the response having a positive Poisson distribution.


Logical. Return the logarithm of the answer?


The probability function of Y is 1 with probability phi, and PosPoisson(lambda) with probability 1-phi. Thus

P(Y=1) = phi + (1-phi) * P(W=1)

where W is distributed as a positive Poisson(lambda) random variate.


doipospois gives the density, poipospois gives the distribution function, qoipospois gives the quantile function, and roipospois generates random deviates.


The argument pstr1 is recycled to the required length, and usually has values which lie in the interval [0,1].

These functions actually allow for the zero-deflated Poisson distribution. Here, pstr1 is also permitted to lie in the interval [-lambda / (expm1(lambda) - lambda), 0]. The resulting probability of a unit count is less than the nominal positive Poisson value, and the use of pstr1 to stand for the probability of a structural 1 loses its meaning. When pstr1 equals -lambda / (expm1(lambda) - lambda) this corresponds to the 0- and 1-truncated Poisson distribution.


T. W. Yee

See Also

Pospois, oapospoisson, oipospoisson, otpospoisson, pospoisson, dpois, poissonff.


lambda <- 3; pstr1 <- 0.2; x <- (-1):7
(ii <- doipospois(x, lambda, pstr1 = pstr1))
table(roipospois(100, lambda, pstr1 = pstr1))
round(doipospois(1:10, lambda, pstr1 = pstr1) * 100)  # Should be similar

## Not run:  x <- 0:10
par(mfrow = c(2, 1))  # One-Inflated Positive Poisson
barplot(rbind(doipospois(x, lambda, pstr1 = pstr1), dpospois(x, lambda)),
        beside = TRUE, col = c("blue", "orange"),
        main = paste("OIPP(", lambda, ", pstr1 = ", pstr1, ") (blue) vs",
                     " PosPoisson(", lambda, ") (orange)", sep = ""),
        names.arg = as.character(x))

deflat.limit <- -lambda / (expm1(lambda) - lambda)  # 0-deflated Pos Poisson
newpstr1 <- round(deflat.limit, 3) + 0.001  # Inside and near the boundary
barplot(rbind(doipospois(x, lambda, pstr1 = newpstr1),
                dpospois(x, lambda)),
        beside = TRUE, col = c("blue","orange"),
        main = paste("ODPP(", lambda, ", pstr1 = ", newpstr1, ") (blue) vs",
                     " PosPoisson(", lambda, ") (orange)", sep = ""),
        names.arg = as.character(x)) 
## End(Not run)

VGAMdata documentation built on March 18, 2022, 8:03 p.m.