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#' Optimal sample allocation calculation for two-level CRTs detecting main effects
#'
#' @description The optimal design of two-level
#' cluster randomized trials (CRTs) detecting main effects is to calculate
#' the optimal sample allocation that minimizes the variance of
#' a treatment effect under a fixed budget, which is approximately the optimal
#' sample allocation that maximizes statistical power under a fixed budget.
#' The optimal design parameters include
#' the level-1 sample size per level-2 unit (\code{n})
#' and the proportion of level-2 clusters/groups to be assigned to treatment (\code{p}).
#' This function solves the optimal \code{n} and/or \code{p}
#' with and without constraints.
#'
#' @inheritParams power.2
#' @inheritParams od.4
#' @param m Total budget, default value is the total costs of sampling 60
#' level-2 units across treatment conditions.
#' @param plot.by Plot the variance by \code{n} and/or \code{p}; default value is
#' plot.by = list(n = "n", p = "p").
#' @param plab The plot label for p,
#' default value is "Proportion Level-2 Units in Treatment: p".
#' @param verbose Logical; print the values of \code{n} and \code{p} if TRUE,
#' otherwise not; default value is TRUE.
#'
#' @return
#' Unconstrained or constrained optimal sample allocation (\code{n} and \code{p}).
#' The function also returns the variance of the treatment effect,
#' function name, design type,
#' and parameters used in the calculation.
#'
#' @export od.2
#'
#' @references
#' Shen, Z., & Kelcey, B. (2020). Optimal sample allocation under unequal
#' costs in cluster-randomized trials. Journal of Educational
#' and Behavioral Statistics, 45(4): 446–474. <https://doi.org/10.3102/1076998620912418>
#'
#' @examples
#' # Unconstrained optimal design #---------
#' myod1 <- od.2(icc = 0.2, r12 = 0.5, r22 = 0.5, c1 = 1, c2 = 5, c1t = 1, c2t = 50,
#' varlim = c(0.01, 0.02))
#' myod1$out # output
#' # Plot by p
#' myod1 <- od.2(icc = 0.2, r12 = 0.5, r22 = 0.5, c1 = 1, c2 = 5, c1t = 1, c2t = 50,
#' varlim = c(0.01, 0.02), plot.by = list(p = 'p'))
#'
#' # Constrained optimal design with n = 20 #---------
#' myod2 <- od.2(icc = 0.2, r12 = 0.5, r22 = 0.5, c1 = 1, c2 = 5, c1t = 1, c2t = 50,
#' n = 20, varlim = c(0.005, 0.025))
#' myod2$out
#' # Relative efficiency (RE)
#' myre <- re(od = myod1, subod= myod2)
#' myre$re # RE = 0.88
#'
#' # Constrained optimal design with p = 0.5 #---------
#' myod3 <- od.2(icc = 0.2, r12 = 0.5, r22 = 0.5, c1 = 1, c2 = 5, c1t = 1, c2t = 50,
#' p = 0.5, varlim = c(0.005, 0.025))
#' myod3$out
#' # Relative efficiency (RE)
#' myre <- re(od = myod1, subod= myod3)
#' myre$re # RE = 0.90
#'
#' # Constrained n and p, no calculation performed #---------
#' myod4 <- od.2(icc = 0.2, r12 = 0.5, r22 = 0.5, c1 = 1, c2 = 5, c1t = 1, c2t = 50,
#' n = 20, p = 0.5, varlim = c(0.005, 0.025))
#' myod4$out
#' # Relative efficiency (RE)
#' myre <- re(od = myod1, subod= myod4)
#' myre$re # RE = 0.83
#'
od.2 <- function(n = NULL, p = NULL, icc = NULL, r12 = NULL, r22 = NULL,
c1 = NULL, c2 = NULL, c1t = NULL, c2t = NULL, m = NULL,
plots = TRUE, plot.by = NULL,
nlim = NULL, plim = NULL, varlim = NULL,
nlab = NULL, plab = NULL, varlab = NULL,
vartitle = NULL,verbose = TRUE) {
funName <- "od.2"
designType <- "two-level CRTs"
if (sum(sapply(list(icc, r12, r22, c1, c2, c1t, c2t),
function(x) is.null(x))) >= 1)
stop("All of 'icc', 'r12', 'r22', 'c1', 'c2',
'c1t', 'c2t' must be specified")
NumberCheck <- function(x) {!is.null(x) && !is.numeric(x)}
if (NumberCheck(icc) || any(0 > icc | icc > 1))
stop("'icc' must be numeric in [0, 1]")
if (sum(sapply(list(r12, r22), function(x) {
NumberCheck(x) || any(0 > x | x > 1)
})) >= 1)
stop("'r12', 'r22' must be numeric in [0, 1]")
if (sum(sapply(list(c1, c2, c1t, c2t), function(x) {
NumberCheck(x) })) >= 1)
stop("'c1', 'c2', 'c1t', 'c2t' must be numeric")
if (!is.null(plot.by) && !is.list(plot.by))
stop("'plot.by' must be in list format (e.g., plot.by = list(n = 'n'))")
if (c1 == 0 && c1t == 0 && is.null(n) && is.null(p))
stop("when c1 and c1t are both zero, one of n or p must be constrained,
please specify a value for n or p")
if (c2 == 0 && c2t == 0 && is.null(n) && is.null(p))
stop("when c2 and c2t are both zero, one of n or p must be constrained,
please specify a value for n or p")
derivative <- quote({
n <- sqrt((1 - icc) * (1 - r12) / (icc * (1 - r22) )) *
sqrt(((1 - p) * c2 + p * c2t)/(( 1 - p) * c1 + p * c1t))
p - sqrt((c1 * n + c2) / (c1t * n + c2t)) /
(1 + sqrt((c1 * n + c2) / (c1t * n + c2t)))
})
par <- list(icc = icc, r12 = r12, r22 = r22, c1 = c1, c2 = c2,
c1t =c1t, c2t = c2t, n = n, p = p)
if (is.null(p) && is.null(n)) {
p <- stats::uniroot(function(p) eval(derivative), interval = c(0, 1))$root
n <- sqrt((1 - icc) * (1 - r12) / (icc * (1 - r22) )) *
sqrt(((1 - p) * c2 + p * c2t)/(( 1 - p) * c1 + p * c1t))
} else if (!is.null(n) && is.null(p)) {
if (!is.numeric(n) || n <= 0)
stop("constrained 'n' must be numeric with n > 0")
p <- sqrt((c1 * n + c2) / (c1t * n + c2t)) /
(1 + sqrt((c1 * n + c2)/(c1t * n + c2t)))
} else if (!is.null(p) && is.null(n)) {
if (!is.numeric(p) || any(p <=0 | p >= 1))
stop("constrained 'p' must be numeric in (0, 1)")
n <- sqrt(( 1 - icc) * (1 - r12) / (icc * (1 - r22))) *
sqrt(((1 - p) * c2 + p * c2t) / ((1 - p) * c1 + p * c1t))
} else if (!is.null(p) && !is.null(n)) {
if (!is.numeric(n) || n <= 0)
stop("constrained 'n' must be numeric with n > 0")
if (!is.numeric(p) || any(p <=0 | p >= 1))
stop("constrained 'p' must be numeric in (0, 1)")
cat("===============================\n",
"Both p and n are constrained, there is no calculation from other parameters",
".\n===============================\n", sep = "")
}
if (verbose == TRUE) {
if (!is.null(par$n)) {
cat("The constrained level-1 sample size per level-2 unit (n) is ", n, ".\n", sep = "")
} else {
cat("The optimal level-1 sample size per level-2 unit (n) is ", n, ".\n", sep = "")
}
if (!is.null(par$p)) {
cat("The constrained proportion of level-2 units in treatment (p) is ", p, ".\n", "\n", sep = "")
} else {
cat("The optimal proportion of level-2 units in treatment (p) is ", p, ".\n", "\n" ,sep = "")
}
}
m <- ifelse(!is.null(m), m, 60 * (p * (c1t * n + c2t) + (1 - p) * (c1 * n + c2)))
var.expr <- quote({
J <- m / ((1 - p) * (c1 * n + c2)
+ p * (c1t * n + c2t))
(icc * (1 - r22) + (1 - icc) * (1 - r12) / n )/ (p * (1 - p) * J)
})
Var <- eval(var.expr)
par <- c(par, list(m = m))
out <- list(n = n, p = p, var = Var)
od.out <- list(funName = funName, designType = designType,
par = par, out = out)
limFun <- function(x, y) {
if (!is.null(x) && length(x) == 2 && is.numeric(x)) {x} else {y}
}
nlim <- limFun(x = nlim, y = c(2, 50))
plim <- limFun(x = plim, y = c(0, 1))
varlim <- limFun(x = varlim, y = c(0, 0.05))
labFun <- function(x, y) {
if (!is.null(x) && length(x) == 1 && is.character(x)) {x} else {y}
}
nlab <- labFun(x = nlab, y = "Level-1 Sample Size: n")
plab <- labFun(x = plab, y = "Proportion Level-2 Units in Treatment: p")
varlab <- labFun(x = varlab, y = "Variance")
vartitle <- labFun(x = vartitle, y = "")
plotbyFun <- function(x, y) {
if (!is.null(x) && is.list(x)) {x} else {y}
}
plot.by <- plotbyFun(x = plot.by, y = list(n = "n", p = "p"))
nrange <- seq(nlim[1], nlim[2], by = 1)
prange <- seq(plim[1] + 0.05, plim[2] - 0.05, by = 0.01)
if (length(plot.by) == 2) figure <- par(mfrow = c (1, 2))
if (length(plot.by) == 1) figure <- par(mfrow = c (1, 1))
if (plots) {
if (!is.null(plot.by$n)) {
plot.y <- NULL
for (n in nrange)
plot.y <- c(plot.y, eval(var.expr))
graphics::plot(nrange, plot.y,
type = "l", lty = 1,
xlim = nlim, ylim = varlim,
xlab = nlab, ylab = varlab,
main = vartitle, col = "black")
n <- out$n
graphics::abline(v = n, lty = 2, col = "Blue")
}
if (!is.null(plot.by$p)) {
plot.y <- NULL
for (p in prange)
plot.y <- c(plot.y, eval(var.expr))
graphics::plot(prange, plot.y,
type = "l", lty = 1,
xlim = plim, ylim = varlim,
xlab = plab, ylab = varlab,
main = vartitle, col = "black")
p <- out$p
graphics::abline(v = p, lty = 2, col = "Blue")
}
}
par(figure)
return(od.out)
}
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