Description Usage Arguments Value Author(s) Examples
This function calculates and plots the precipitation titration curve for an analyte and a titrant that form a precipitate with a 1:1 stoichiometry. The calculation uses a single master equation that finds the volume of titrant needed to achieve a fixed concentration of the analyte, expressed as pAnalyte, as outlined in R. de Levie's Principles of Quantitative Chemical Analysis (McGraw-Hill, 1997).
1 2 |
conc.analyte |
Molar concentration of the analyte; defaults to 0.025 M. |
conc.titrant |
Molar concentration of the titrant; defaults to 0.050 M. |
vol.analyte |
The initial volume, in mL, of the solution containing the analyte; defaults to 50.00 mL. |
pksp |
The pKsp value for the precipitate; defaults to 16.08, which is the pKsp for AgI. |
plot |
Logical; if TRUE, plots the titration curve. |
eqpt |
Logical; if TRUE, draws a vertical line at the titration curve's equivalence point. |
overlay |
Logical; if TRUE, adds the current titration curve to the existing titration curve. |
... |
Additional arguments to pass to |
A two-column data frame that contains the volume of titrant in the first column and the solution's pAnalyte in the second column. Also produces a plot of the titration curve with options to display the equivalence point and to overlay titration curves.
David T. Harvey, DePauw University. harvey@depauw.edu
1 2 3 4 5 6 7 8 | ### Simple titration curve with equivalence point
ex13 = ppt_analyte(eqpt = TRUE)
head(ex13)
### Overlay titration curves using different pKsp values
ppt_analyte(pksp = 16, eqpt = TRUE)
ppt_analyte(pksp = 14, overlay = TRUE)
ppt_analyte(pksp = 12, overlay = TRUE)
|
volume p.analyte
1 0.3037750 1.61
2 0.6836692 1.62
3 1.0605006 1.63
4 1.4342075 1.64
5 1.8047308 1.65
6 2.1720140 1.66
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