View source: R/get1stOfRepeatedByCol.R
get1stOfRepeatedByCol | R Documentation |
get1stOfRepeatedByCol
sorts matrix 'mat' and extracts only 1st occurance of values in column 'sortBy'.
Returns then non-redundant matrix (ie for column 'sortBy', if 'markIfAmbig' specifies existing col, mark ambig there).
Note : problem when sortSupl or sortBy not present (or not intended for use)
get1stOfRepeatedByCol(
mat,
sortBy = "seq",
sortSupl = "ty",
asFirstLast = c("full", "inter"),
markIfAmbig = c("ambig", "seqNa"),
asList = FALSE,
abmiPref = "_"
)
mat |
(matrix or data.frame) numeric vector to be tested |
sortBy |
column name for which elements should be made unique, numeric or character column; 'sortSupl' .. add'l colname to always select specific 1st) |
sortSupl |
default="ty" |
asFirstLast |
(character,length=2) to force specific strings from coluln 'sortSupl' as first and last when selecting 1st of repeated terms, default=c("full","inter") |
markIfAmbig |
(character,length=2) 1st will be set to 'TRUE' if ambiguous/repeated, 2nd will get (heading) prefix, default=c("ambig","seqNa") |
asList |
(logical) to return list with non-redundant ('unique') and removed lines ('repeats') |
abmiPref |
(character) prefix to note ambiguous entries/terms, default="_" |
depending on 'asList' either list with non-redundant ('unique') and removed lines ('repeats')
firstOfRepeated
for (more basic) treatment of simple vector, nonAmbiguousNum
for numeric use (much faster !!!)
aa <- cbind(no=as.character(1:20),seq=sample(LETTERS[1:15],20,repl=TRUE),
ty=sample(c("full","Nter","inter"),20,repl=TRUE),ambig=rep(NA,20),seqNa=1:20)
get1stOfRepeatedByCol(aa)
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