# Functions copied from selectiveInference package
# See: https://github.com/selective-inference/R-software/
# blob/master/selectiveInference/R/funs.groupfs.R
TC_surv <- function(TC, sigma, df, E) {
if (length(E) == 0) {
stop("Empty TC support")
}
# Sum truncated cdf over each part of E
denom <- do.call(sum, lapply(1:nrow(E), function(v) {
tchi_interval(E[v,1], E[v,2], sigma, df)
}))
# Sum truncated cdf from observed value to max of
# truncation region
numer <- do.call(sum, lapply(1:nrow(E), function(v) {
lower <- E[v,1]
upper <- E[v,2]
if (upper > TC) {
# Observed value is left of this interval's right endpoint
if (lower < TC) {
# Observed value is in this interval
return(tchi_interval(TC, upper, sigma, df))
} else {
# Observed value is not in this interval
return(tchi_interval(lower, upper, sigma, df))
}
} else {
# Observed value is right of this entire interval
return(0)
}
}))
# Survival function
value <- numer/denom
# Force p-value to lie in the [0,1] interval
# in case of numerical issues
value <- max(0, min(1, value))
value
}
tchi_interval <- function(lower, upper, sigma, df) {
a <- (lower/sigma)^2
b <- (upper/sigma)^2
if (b == Inf) {
integral <- pchisq(a, df, lower.tail = FALSE)
} else {
integral <- pchisq(b, df) - pchisq(a, df)
}
if ((integral < .Machine$double.eps) && (b < Inf)) {
integral <- num_int_chi(a, b, df)
}
return(integral)
}
num_int_chi <- function(a, b, df, nsamp = 10000) {
grid <- seq(from=a, to=b, length.out=nsamp)
integrand <- dchisq(grid, df)
return((b-a)*mean(integrand))
}
grid.search <- function(grid, fun, val1, val2, gridpts=100, griddepth=2) {
n = length(grid)
vals = fun(grid)
ii = which(vals >= val1)
jj = which(vals <= val2)
if (length(ii)==0) return(c(grid[n],Inf)) # All vals < val1
if (length(jj)==0) return(c(-Inf,grid[1])) # All vals > val2
# RJT: the above logic is correct ... but for simplicity, instead,
# we could just return c(-Inf,Inf)
i1 = min(ii); i2 = max(jj)
if (i1==1) lo = -Inf
else lo = grid.bsearch(grid[i1-1],grid[i1],fun,val1,gridpts,
griddepth-1,below=TRUE)
if (i2==n) hi = Inf
else hi = grid.bsearch(grid[i2],grid[i2+1],fun,val2,gridpts,
griddepth-1,below=FALSE)
return(c(lo,hi))
}
grid.bsearch <- function(left, right, fun, val, gridpts=100, griddepth=1, below=TRUE) {
n = gridpts
depth = 1
while (depth <= griddepth) {
grid = seq(left,right,length=n)
vals = fun(grid)
if (below) {
ii = which(vals >= val)
if (length(ii)==0) return(grid[n]) # All vals < val (shouldn't happen)
if ((i0=min(ii))==1) return(grid[1]) # All vals > val (shouldn't happen)
left = grid[i0-1]
right = grid[i0]
}
else {
ii = which(vals <= val)
if (length(ii)==0) return(grid[1]) # All vals > val (shouldn't happen)
if ((i0=max(ii))==n) return(grid[n]) # All vals < val (shouldn't happen)
left = grid[i0]
right = grid[i0+1]
}
depth = depth+1
}
return(ifelse(below, left, right))
}
tnorm.surv <- function(z, mean, sd, a, b, bits=NULL) {
z = max(min(z,b),a)
# Check silly boundary cases
p = numeric(length(mean))
p[mean==-Inf] = 0
p[mean==Inf] = 1
# Try the multi precision floating point calculation first
o = is.finite(mean)
mm = mean[o]
pp = mpfr.tnorm.surv(z,mm,sd,a,b,bits)
# If there are any NAs, then settle for an approximation
oo = is.na(pp)
if (any(oo)) pp[oo] = bryc.tnorm.surv(z,mm[oo],sd,a,b)
p[o] = pp
return(p)
}
bryc.tnorm.surv <- function(z, mean=0, sd=1, a, b) {
z = (z-mean)/sd
a = (a-mean)/sd
b = (b-mean)/sd
n = length(mean)
term1 = exp(z*z)
o = a > -Inf
term1[o] = ff(a[o])*exp(-(a[o]^2-z[o]^2)/2)
term2 = rep(0,n)
oo = b < Inf
term2[oo] = ff(b[oo])*exp(-(b[oo]^2-z[oo]^2)/2)
p = (ff(z)-term2)/(term1-term2)
# Sometimes the approximation can give wacky p-values,
# outside of [0,1] ..
#p[p<0 | p>1] = NA
p = pmin(1,pmax(0,p))
return(p)
}
ff <- function(z) {
return((z^2+5.575192695*z+12.7743632)/
(z^3*sqrt(2*pi)+14.38718147*z*z+31.53531977*z+2*12.77436324))
}
# calculation via Rmpfr is commented out in order to
# prevent warnings when checking the package
mpfr.tnorm.surv <- function(z, mean=0, sd=1, a, b, bits=NULL) {
# If bits is not NULL, then we are supposed to be using Rmpf
# (note that this was fail if Rmpfr is not installed; but
# by the time this function is being executed, this should
# have been properly checked at a higher level; and if Rmpfr
# is not installed, bits would have been previously set to NULL)
# if (!is.null(bits)) {
# z = Rmpfr::mpfr((z-mean)/sd, precBits=bits)
# a = Rmpfr::mpfr((a-mean)/sd, precBits=bits)
# b = Rmpfr::mpfr((b-mean)/sd, precBits=bits)
# return(as.numeric((Rmpfr::pnorm(b)-Rmpfr::pnorm(z))/
# (Rmpfr::pnorm(b)-Rmpfr::pnorm(a))))
# }
# Else, just use standard floating point calculations
z = (z-mean)/sd
a = (a-mean)/sd
b = (b-mean)/sd
return((pnorm(b)-pnorm(z))/(pnorm(b)-pnorm(a)))
}
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