Description Usage Arguments Details Value Author(s) References Examples
Given a vector of numeric values of real values
represented in log form, logMeanExpLogs
computes
the logarithm of the mean of the (exponentiated) values.
logCumMeanExpLogs
computes the logarithm of the
cumulative mean.
1 |
v |
A vector of (log) values |
Given a vector of values of log values v, one could
compute log(mean(exp(v)))
in R. However,
exponentiating and summing will cause a loss of
precision, and possibly an overflow. These functions use
the identity
log(e^a + e^b) = a + log[ 1 + e^(b-a) ]
and the method of computing log(1+e^x) that avoids overflow (see the references). The code is written in C for very fast computations.
logMeanExpLogs
returns a single value;
logCumMeanExpLogs
returns a vector of values of
the same length as v.
Richard D. Morey (richarddmorey@gmail.com)
For details of the approximation of log(1+e^x) used to prevent loss of precision, see http://www.codeproject.com/Articles/25294/Avoiding-Overflow-Underflow-and-Loss-of-Precision.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | # Sample 100 values
y = log(rexp(100,1))
# These will give the same value,
# since e^y is "small"
logMeanExpLogs(y)
log(mean(exp(y)))
# We can make e^x overflow by multiplying
# e^y by e^1000
largeVals = y + 1000
# This will return 1000 + log(mean(exp(y)))
logMeanExpLogs(largeVals)
# This will overflow
log(mean(exp(largeVals)))
|
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