Description Usage Arguments Details Value Note Author(s) See Also Examples
Given a vector of n variables, and a set of n (nonlinear) equations in these variables,
estimates the root of the equations, i.e. the variable values where all function values = 0.
Assumes a full Jacobian matrix, uses the Newton-Raphson method.
1 2 3 4 5 6 |
f |
function for which the root is sought; it must return a vector
with as many values as the length of |
start |
vector containing initial guesses for the unknown x;
if |
maxiter |
maximal number of iterations allowed. |
rtol |
relative error tolerance, either a scalar or a vector, one value for each element in the unknown x. |
atol |
absolute error tolerance, either a scalar or a vector, one value for each element in x. |
ctol |
a scalar. If between two iterations, the maximal change in the variable values is less than this amount, then it is assumed that the root is found. |
useFortran |
logical, if |
positive |
if |
jacfunc |
if not If the Jacobian is a full matrix, If the Jacobian is banded, |
jactype |
the structure of the Jacobian, one of "fullint", "fullusr",
"bandusr", "bandint", or "sparse" - either full or banded and
estimated internally or by the user, or arbitrary sparse.
If the latter, then the solver will call, If the Jacobian is arbitrarily "sparse", then it will be calculated by
the solver (i.e. it is not possible to also specify |
verbose |
if |
bandup |
number of non-zero bands above the diagonal, in case the Jacobian is banded. |
banddown |
number of non-zero bands below the diagonal, in case the jacobian is banded. |
parms |
vector or list of parameters used in |
... |
additional arguments passed to function |
start
gives the initial guess for each variable; different initial
guesses may return different roots.
The input parameters rtol
, and atol
determine the error
control performed by the solver.
The solver will control the vector
e of estimated local errors in f, according to an
inequality of the form max-norm of ( e/ewt )
<= 1, where ewt is a vector of positive error
weights. The values of rtol
and atol
should all be
non-negative.
The form of ewt is:
\bold{rtol} * abs(\bold{x}) + \bold{atol}
where multiplication of two vectors is element-by-element.
In addition, the solver will stop if between two iterations, the maximal
change in the values of x is less than ctol
.
There is no checking whether the requested precision exceeds the capabilities of the machine.
a list containing:
root |
the location (x-values) of the root. |
f.root |
the value of the function evaluated at the |
iter |
the number of iterations used. |
estim.precis |
the estimated precision for |
The Fortran implementation of the Newton-Raphson method function (the default) is generally faster than the R implementation. The R implementation has been included for didactic purposes.
multiroot
makes use of function stode
.
Technically, it is just a wrapper around function stode
.
If the sparsity structure of the Jacobian is known, it may be more efficiently
to call stode, stodes, steady, steady.1D, steady.2D, steady.3D
.
It is NOT guaranteed that the method will converge to the root.
Karline Soetaert <karline.soetaert@nioz.nl>
stode
, which uses a different function call.
uniroot.all
, to solve for all roots of one (nonlinear) equation
steady
, steady.band
, steady.1D
,
steady.2D
, steady.3D
, steady-state solvers,
which find the roots of ODEs or PDEs. The function call differs from
multiroot
.
jacobian.full
, jacobian.band
, estimates the
Jacobian matrix assuming a full or banded structure.
gradient
, hessian
, estimates the gradient
matrix or the Hessian.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 | ## =======================================================================
## example 1
## 2 simultaneous equations
## =======================================================================
model <- function(x) c(F1 = x[1]^2+ x[2]^2 -1,
F2 = x[1]^2- x[2]^2 +0.5)
(ss <- multiroot(f = model, start = c(1, 1)))
## =======================================================================
## example 2
## 3 equations, two solutions
## =======================================================================
model <- function(x) c(F1 = x[1] + x[2] + x[3]^2 - 12,
F2 = x[1]^2 - x[2] + x[3] - 2,
F3 = 2 * x[1] - x[2]^2 + x[3] - 1 )
# first solution
(ss <- multiroot(model, c(1, 1, 1), useFortran = FALSE))
(ss <- multiroot(f = model, start = c(1, 1, 1)))
# second solution; use different start values
(ss <- multiroot(model, c(0, 0, 0)))
model(ss$root)
## =======================================================================
## example 2b: same, but with parameters
## 3 equations, two solutions
## =======================================================================
model2 <- function(x, parms)
c(F1 = x[1] + x[2] + x[3]^2 - parms[1],
F2 = x[1]^2 - x[2] + x[3] - parms[2],
F3 = 2 * x[1] - x[2]^2 + x[3] - parms[3])
# first solution
parms <- c(12, 2, 1)
multiroot(model2, c(1, 1, 1), parms = parms)
multiroot(model2, c(0, 0, 0), parms = parms*2)
## =======================================================================
## example 3: find a matrix
## =======================================================================
f2<-function(x) {
X <- matrix(nrow = 5, x)
X %*% X %*% X -matrix(nrow = 5, data = 1:25, byrow = TRUE)
}
x <- multiroot(f2, start = 1:25 )$root
X <- matrix(nrow = 5, x)
X%*%X%*%X
|
$root
[1] 0.5000000 0.8660254
$f.root
F1 F2
2.323138e-08 2.323308e-08
$iter
[1] 5
$estim.precis
[1] 2.323223e-08
$root
[1] 1 2 3
$f.root
F1 F2 F3
3.087877e-10 4.794444e-09 -8.678146e-09
$iter
[1] 6
$estim.precis
[1] 4.593792e-09
$root
[1] 1 2 3
$f.root
F1 F2 F3
3.087877e-10 4.794444e-09 -8.678146e-09
$iter
[1] 6
$estim.precis
[1] 4.593792e-09
$root
[1] -0.2337207 1.3531901 3.2985649
$f.root
F1 F2 F3
1.092413e-08 1.920978e-07 -4.850423e-08
$iter
[1] 10
$estim.precis
[1] 8.384205e-08
F1 F2 F3
1.092413e-08 1.920978e-07 -4.850423e-08
$root
[1] 1 2 3
$f.root
F1 F2 F3
3.087877e-10 4.794444e-09 -8.678146e-09
$iter
[1] 6
$estim.precis
[1] 4.593792e-09
$root
[1] -0.6406658 1.2471383 4.8366856
$f.root
F1 F2 F3
3.105072e-12 1.661515e-10 -2.408385e-11
$iter
[1] 11
$estim.precis
[1] 6.444682e-11
[,1] [,2] [,3] [,4] [,5]
[1,] 1 2 3 4 5
[2,] 6 7 8 9 10
[3,] 11 12 13 14 15
[4,] 16 17 18 19 20
[5,] 21 22 23 24 25
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