Description Usage Arguments Author(s) References Examples
This function calculates value of the pgf's first derivative of the hyper Poisson distribution.
1 | pgfDhyperpoisson(s, params)
|
s |
Value of the parameter of the pgf. It should be from interval [-1,1]. In the opposite pgf diverges. |
params |
List of the parameters of the hyper Poisson distribution, such that params<-c(theta,lambda), where both parameters are positive. |
S. Nadarajah, B. V. Popovic, M. M. Ristic
Johnson N, Kotz S, Kemp A (1992) Univariate Discrete Distributions, John Wiley and Sons, New York
Hankin R.K.S, Lee A (2006) A new family of non-negative distributions. Australia and New Zealand Journal of Statistics 48(1): 67(78)
http://www.am.qub.ac.uk/users/g.gribakin/sor/Chap3.pdf
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | params<-c(.7,3)
pgfDhyperpoisson(.5,params)
## The function is currently defined as
pgfDhyperpoisson <- function(s,params) {
require(hypergeo)
k<-s[abs(s)>1]
if (length(k)>0)
warning("At least one element of the vector s are out of interval [-1,1]")
if (length(params)<2)
stop("At least one value in params is missing")
if (length(params)>2)
stop("The length of params is 2")
theta<-params[1]
lambda<-params[2]
if (theta<=0)
stop ("Parameter theta must be positive")
if (lambda<=0)
stop ("Parameter lambda must be positive")
theta*genhypergeo(2,lambda+1,theta*s)/(lambda*genhypergeo(1,lambda,theta))
}
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