Description Usage Arguments Value Examples
Use this function to determine if a drug combination is part of a vector of other drug combinations. We take care only of pair-wise drug combinations and an internal check is done for alternative drug names, e.g. we check if A-B combination is included, but also for B-A.
1 | is_comb_element_of(drug.comb, comb.vector)
|
drug.comb |
a string in the form A-B (no spaces between the names and the hyphen '-') |
comb.vector |
a character vector of drug combinations, each one in the form drugname.1-drugname.2 |
logical, depending if the drug combination is element of the given vector or not.
1 2 3 4 5 6 7 | # TRUE
is_comb_element_of("A-B", c("E-F", "A-B"))
is_comb_element_of("B-A", c("E-F", "A-B"))
# FALSE
is_comb_element_of("A-B", c("E-F", "A-D"))
is_comb_element_of("A-B", c())
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