Nothing
fn1 <- function(ss,a,n,M){ ## getting s_1 and checking for solution for 'at most' case...
## ss has to be in order from 2 till 'l'
res <- numeric(0)
s1 <- (n-sum(ss*a[-1]))/a[1]
if (s1>=0 && s1==floor(s1) && sum(c(s1,ss))<= M)
res <- c(s1,ss)
res
}
## function to work through the loops for 'at most' case......
recursive.fn1 <- function(w,b,a,n,M){
S <- rep(0,0)
d <- 0
if(length(b)) {
for( i in seq(0,b[1]) ) {
if (length(b) >1){
d<-sum(w*a[length(a):(length(a)-length(w)+1)])+i*a[length(b)+1]
b[2] <- floor((n-d)/a[length(b)])
}
S <- c(S, Recall( c(w,i), b[-1],a,n,M))
}
} else {
return(fn1(rev(w),a,n,M))
}
S
}
fn2 <- function(ss,a,n,M){ ## getting s_{l-1} and s_l and checking for solution for 'exactly' case...
## ss has to be in order from 3 till 'l'
res <- numeric(0)
l <- length(a)
s2 <- (n-M*a[1] - sum(ss[length(ss):1]*(a[c(l:3)]-a[1])))/(a[2]-a[1])
if (s2>=0 && s2==floor(s2) && sum(c(s2,ss))<= M ) {
s1 <- M- sum(c(s2,ss))
res <- c(s1,s2,ss)
}
res
}
## function to work through the loops for 'exactly' case......
recursive.fn2 <- function(w,b,a,n,M){
S <- rep(0,0)
d <- 0
if(length(b)) {
if (sum(is.finite(b))==length(b)) {
for( i in seq(0,b[1]) ) {
if (length(b) >1){
d<-sum(w*(a[length(a):(length(a)-length(w)+1)]-a[1]))+i*(a[length(b)+1] -a[1])
b[2] <- max(0, floor((n-M*a[1]-d)/(a[length(b)]-a[1])) )
}
S <- c(S, Recall( c(w,i), b[-1],a,n,M))
}
} else S <- c(S, Recall( c(w,0), b[-1],a,n,M)) # return(fn2(rev(w),a,n,M)) ?????? most probably not correct here!!!!
} else {
return(fn2(rev(w),a,n,M))
}
S
}
nlde <- function(a,n,M=NULL,at.most=TRUE,option=0){
## function to solve nonnegative linear diophantine equation (NLDE):
## a_1*s_1 +a_2*s_2 +...+ a_l*s_l =n
## 'a' is an l-vector of positive integers (coefficients of the left-hand-side of NLDE) with l>= 2
## 'n' is positive integer of the right-hand-side of NLDE
## vector of s are unknowns to be found
## 'at.most' is logical with TRUE standing for constructing all partitions of n into at most M parts and FALSE for exactly M parts
## 'M' is a positive integer, M <= n
## 'option' when set to '1' solves nlde 0-1 problem (nlde has only 0 -1 solutions),
## when 'option=2' (or > 2) solves 0-1 NLD inequality
if (length(a) < 2) {stop("length of vector 'a' has to be more than 1")}
if (!isTRUE(all(a == floor(a))) || !isTRUE(all(a > 0))) stop("'a' must only contain positive integer values")
if (length(n) >1) {stop("'n' has to be a positive integer")}
if (!isTRUE(n == floor(n)) || !isTRUE(n > 0)) {stop("'n' has to be a positive integer")}
if (!is.logical(at.most)) stop("'at.most' must be TRUE or FALSE")
if (is.null(M)) M <- floor(n/min(a))
else { if (!isTRUE(M == floor(M)) || !isTRUE(M > 0)) {stop("'M' has to be a positive integer")}
if (M > n) stop("'M' has to be less or equal to 'n'")
}
if (option < 0) warning("'option' must be 0 or positive, ignored")
ra <- rank(a, ties.method= "first")
a <- sort(a)
l <- length(a)
if (option > 1) { ## solving 01 inequality...
a1 <- c(a[ra],1) ## adding a slack variable
ra <- rank(a1, ties.method= "first")
M <- floor(n/min(a1))
a <- sort(a1)
l <- length(a1)
}
out <-numeric(0)
## solving nlde...
if (at.most){ ## getting partitions of n into AT MOST M parts...
b <- c(floor(n/a[l]),rep(NA,l-2))
out <- recursive.fn1(numeric(0), b,a,n,M)
} else { ## getting partitions of n into EXACTLY M parts...
b <- c(floor((n-M*a[1])/(a[l]-a[1])), rep(NA, l-3))
out <- recursive.fn2(numeric(0), b,a,n,M)
}
if (length(out)==0)
{out<- NULL; n.sol <-0 }
else {
dim(out) <- c(l,length(out)/l)
out <- as.matrix(out[ra,],l,length(out)/l) ## going back to original unsorted coefficients
if (option > 1)
out <- out[1:(l-1),] ## remove the last row of slacks
if (option > 0){
check01 <- function(vec) all(vec== 0 | vec== 1)
ind <- apply(out,2,check01)
out <- as.matrix(out[,ind])
}
if (length(out)==0) {
out <- NULL; n.sol <-0
} else {
rownames(out) <- paste("s", c(1:dim(out)[1]), sep="")
colnames(out) <- paste(c("sol."), seq(1:dim(out)[2]), sep="")
n.sol <- ncol(out)
}
}
object <- list()
object$p.n <- n.sol
object$solutions <- out
class(object)<-"nlde"
object
} ## end nlde
## printing nlde solutions...
print.nlde <- function (x,...)
## default print function for "nlde" objects
{
cat("\n")
if (is.null(x$solutions)) cat("no solutions", "\n")
else {
cat("The number of solutions: ", x$p.n, "\n", sep = "")
cat("\nSolutions:\n")
printCoefmat(x$solutions, ...)
cat("\n")
}
invisible(x)
}
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