View source: R/combinatorics.R

get.n | R Documentation |

Returns the number of grains that need to be analysed to decrease the likelihood of missing any fraction greater than a given size below a given level.

```
get.n(p = 0.05, f = 0.05)
```

`p` |
the probability that all n grains in the sample have missed
at least one fraction of size |

`f` |
the size of the smallest resolvable fraction (0<f<1) |

`n, ` |
the number of grains in the sample |

the number of grains needed to reduce the chance of missing
at least one fraction f of the total population to less than `p`

Vermeesch, Pieter. "How many grains are needed for a provenance study?." Earth and Planetary Science Letters 224.3 (2004): 441-451.

```
# number of grains required to be 99% that no fraction greater than 5% was missed:
print(get.n(0.01))
# number of grains required to be 90% that no fraction greater than 10% was missed:
print(get.n(p=0.1,f=0.1))
```

Embedding an R snippet on your website

Add the following code to your website.

For more information on customizing the embed code, read Embedding Snippets.