Description Usage Arguments Details Value Author(s) Examples
View source: R/phylogeneticUtilities.R
phy.nodetimes
is a function to collect all nodes (and times) that are within a particular time fraction of the total temporal extent of a phylogeny
1 | phy.nodetimes(phy, time.range = c(0, 0), proportion = TRUE)
|
phy |
a phylogenetic tree of class |
time.range |
the temporal slice of the tree defining the bounds for extracted nodes |
proportion |
Boolean; whether |
Given a temporal fraction of a phylogeny, this function will return all contained nodes (and
branching times if desired). If used with spacodi.by.nodes
, one could conduct significance testing of Bst
through
particular time slices of the phylogeny. Note: when using proportion=TRUE
, '0' is regarded as the present, '1' as the root of the tree (e.g., start.time=1.0
and
stop.time=0.8
gathers nodes for the basalmost or most rootward 20 percent of the temporal extent of the tree).
A named vector of times (whose names are node labels; see nodelabels
for the function used to label nodes).
Jonathan Eastman
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | ## an example of comparing observed and expected Bst at nodes ##
data(sp.example)
attach(sp.example)
s=spl
p=phy
# get nodes for a time-slice
n.t=phy.nodetimes(phy=p,time.range=c(0.25,0.75))
# get Bsts for nodes
o=spacodi.by.nodes(sp.plot=s, phy=p, obs.only=TRUE)[[1]]
obs=o[!is.na(match(o[,"node.ID"], names(n.t))),1]
# compile expected Bst-values from data reshuffling
spacodi.by.nodes(sp.plot=s, phy=p, n.rep=5, method="1s")[[2]]->exps
e=exps[!is.na(match(row.names(exps), names(n.t))),]
exp=unname(unlist(e))
# randomization test of observed and expected Bst
resamp.test(obs=obs, exp=exp, iter=100, two.tailed=TRUE)
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