#' Day 16: Packet Decoder
#'
#' As you leave the cave and reach open waters, you receive a transmission from the Elves back on the ship.
#'
#' The transmission was sent using the Buoyancy Interchange Transmission System (BITS), a method of packing numeric expressions into a binary sequence. Your submarine's computer has saved the transmission in hexadecimal (your puzzle input).
#'
#' The first step of decoding the message is to convert the hexadecimal representation into binary. Each character of hexadecimal corresponds to four bits of binary data:
#'
#' 0 = 0000
#' 1 = 0001
#' 2 = 0010
#' 3 = 0011
#' 4 = 0100
#' 5 = 0101
#' 6 = 0110
#' 7 = 0111
#' 8 = 1000
#' 9 = 1001
#' A = 1010
#' B = 1011
#' C = 1100
#' D = 1101
#' E = 1110
#' F = 1111
#'
#' The BITS transmission contains a single packet at its outermost layer which itself contains many other packets. The hexadecimal representation of this packet might encode a few extra 0 bits at the end; these are not part of the transmission and should be ignored.
#'
#' Every packet begins with a standard header: the first three bits encode the packet version, and the next three bits encode the packet type ID. These two values are numbers; all numbers encoded in any packet are represented as binary with the most significant bit first. For example, a version encoded as the binary sequence 100 represents the number 4.
#'
#' Packets with type ID 4 represent a literal value. Literal value packets encode a single binary number. To do this, the binary number is padded with leading zeroes until its length is a multiple of four bits, and then it is broken into groups of four bits. Each group is prefixed by a 1 bit except the last group, which is prefixed by a 0 bit. These groups of five bits immediately follow the packet header. For example, the hexadecimal string `D2FE28` becomes:
#'
#' 110100101111111000101000
#' VVVTTTAAAAABBBBBCCCCC
#'
#' Below each bit is a label indicating its purpose:
#'
#' - The three bits labeled V (110) are the packet version, 6.
#' - The three bits labeled T (100) are the packet type ID, 4, which means the packet is a literal value.
#' - The five bits labeled A (10111) start with a 1 (not the last group, keep reading) and contain the first four bits of the number, 0111.
#' - The five bits labeled B (11110) start with a 1 (not the last group, keep reading) and contain four more bits of the number, 1110.
#' - The five bits labeled C (00101) start with a 0 (last group, end of packet) and contain the last four bits of the number, 0101.
#' - The three unlabeled 0 bits at the end are extra due to the hexadecimal representation and should be ignored.
#'
#' So, this packet represents a literal value with binary representation `011111100101`, which is 2021 in decimal.
#'
#' Every other type of packet (any packet with a type ID other than 4) represent an operator that performs some calculation on one or more sub-packets contained within. Right now, the specific operations aren't important; focus on parsing the hierarchy of sub-packets.
#'
#' An operator packet contains one or more packets. To indicate which subsequent binary data represents its sub-packets, an operator packet can use one of two modes indicated by the bit immediately after the packet header; this is called the length type ID:
#'
#' - If the length type ID is 0, then the next 15 bits are a number that represents the total length in bits of the sub-packets contained by this packet.
#' - If the length type ID is 1, then the next 11 bits are a number that represents the number of sub-packets immediately contained by this packet.
#'
#' Finally, after the length type ID bit and the 15-bit or 11-bit field, the sub-packets appear.
#'
#' For example, here is an operator packet (hexadecimal string `38006F45291200`) with length type ID 0 that contains two sub-packets:
#'
#' 00111000000000000110111101000101001010010001001000000000
#' VVVTTTILLLLLLLLLLLLLLLAAAAAAAAAAABBBBBBBBBBBBBBBB
#'
#' - The three bits labeled V (001) are the packet version, 1.
#' - The three bits labeled T (110) are the packet type ID, 6, which means the packet is an operator.
#' - The bit labeled I (0) is the length type ID, which indicates that the length is a 15-bit number representing the number of bits in the sub-packets.
#' - The 15 bits labeled L (000000000011011) contain the length of the sub-packets in bits, 27.
#' - The 11 bits labeled A contain the first sub-packet, a literal value representing the number 10.
#' - The 16 bits labeled B contain the second sub-packet, a literal value representing the number 20.
#'
#' After reading 11 and 16 bits of sub-packet data, the total length indicated in L (27) is reached, and so parsing of this packet stops.
#'
#' As another example, here is an operator packet (hexadecimal string `EE00D40C823060`) with length type ID 1 that contains three sub-packets:
#'
#' 11101110000000001101010000001100100000100011000001100000
#' VVVTTTILLLLLLLLLLLAAAAAAAAAAABBBBBBBBBBBCCCCCCCCCCC
#'
#' - The three bits labeled V (111) are the packet version, 7.
#' - The three bits labeled T (011) are the packet type ID, 3, which means the packet is an operator.
#' - The bit labeled I (1) is the length type ID, which indicates that the length is a 11-bit number representing the number of sub-packets.
#' - The 11 bits labeled L (00000000011) contain the number of sub-packets, 3.
#' - The 11 bits labeled A contain the first sub-packet, a literal value representing the number 1.
#' - The 11 bits labeled B contain the second sub-packet, a literal value representing the number 2.
#' - The 11 bits labeled C contain the third sub-packet, a literal value representing the number 3.
#'
#' After reading 3 complete sub-packets, the number of sub-packets indicated in L (3) is reached, and so parsing of this packet stops.
#'
#' For now, parse the hierarchy of the packets throughout the transmission and add up all of the version numbers.
#'
#' Here are a few more examples of hexadecimal-encoded transmissions:
#'
#' - `8A004A801A8002F478` represents an operator packet (version 4) which contains an operator packet (version 1) which contains an operator packet (version 5) which contains a literal value (version 6); this packet has a version sum of 16.
#' - `620080001611562C8802118E34` represents an operator packet (version 3) which contains two sub-packets; each sub-packet is an operator packet that contains two literal values. This packet has a version sum of 12.
#' - `C0015000016115A2E0802F182340` has the same structure as the previous example, but the outermost packet uses a different length type ID. This packet has a version sum of 23.
#' - `A0016C880162017C3686B18A3D4780` is an operator packet that contains an operator packet that contains an operator packet that contains five literal values; it has a version sum of 31.
#'
#' Decode the structure of your hexadecimal-encoded BITS transmission; what do you get if you add up the version numbers in all packets?
#'
#' ## Part Two:
#'
#' Now that you have the structure of your transmission decoded, you can calculate the value of the expression it represents.
#'
#' Literal values (type ID 4) represent a single number as described above. The remaining type IDs are more interesting:
#'
#' - Packets with type ID 0 are sum packets - their value is the sum of the values of their sub-packets. If they only have a single sub-packet, their value is the value of the sub-packet.
#' - Packets with type ID 1 are product packets - their value is the result of multiplying together the values of their sub-packets. If they only have a single sub-packet, their value is the value of the sub-packet.
#' - Packets with type ID 2 are minimum packets - their value is the minimum of the values of their sub-packets.
#' - Packets with type ID 3 are maximum packets - their value is the maximum of the values of their sub-packets.
#' - Packets with type ID 5 are greater than packets - their value is 1 if the value of the first sub-packet is greater than the value of the second sub-packet; otherwise, their value is 0. These packets always have exactly two sub-packets.
#' - Packets with type ID 6 are less than packets - their value is 1 if the value of the first sub-packet is less than the value of the second sub-packet; otherwise, their value is 0. These packets always have exactly two sub-packets.
#' - Packets with type ID 7 are equal to packets - their value is 1 if the value of the first sub-packet is equal to the value of the second sub-packet; otherwise, their value is 0. These packets always have exactly two sub-packets.
#'
#' Using these rules, you can now work out the value of the outermost packet in your BITS transmission.
#'
#' For example:
#'
#' - `C200B40A82` finds the sum of 1 and 2, resulting in the value 3.
#' - `04005AC33890` finds the product of 6 and 9, resulting in the value 54.
#' - `880086C3E88112` finds the minimum of 7, 8, and 9, resulting in the value 7.
#' - `CE00C43D881120` finds the maximum of 7, 8, and 9, resulting in the value 9.
#' - `D8005AC2A8F0` produces 1, because 5 is less than 15.
#' - `F600BC2D8F` produces 0, because 5 is not greater than 15.
#' - `9C005AC2F8F0` produces 0, because 5 is not equal to 15.
#' - `9C0141080250320F1802104A08` produces 1, because 1 + 3 = 2 * 2.
#'
#' What do you get if you evaluate the expression represented by your hexadecimal-encoded BITS transmission?
#'
#' @source <https://adventofcode.com/2021/day/16>
#' @name day16
NULL
#' @rdname day16
#' @param x A hexadecimal string.
#' @export
to_bits <- function(x) {
ints <- strtoi(strsplit(x, '')[[1]], 16)
bits <- sapply(ints, \(n) tail(rev(as.numeric(intToBits(n))), 4))
as.vector(bits)
}
#' @rdname day16
#' @param bits A vector of bits.
#' @param depth Nesting level of the sub-packet.
#' @param rem_subs How many sub-packets are left (for length type ID 1).
#' @export
packet_versions <- function(bits, depth = 0, rem_subs = Inf, eval = FALSE) {
acc <- 0
while (any(bits > 0) & rem_subs > 0) {
rem_subs <- rem_subs - 1
version <- binary_to_int(bits[1:3])
acc <- acc + version
type <- binary_to_int(bits[4:6])
bits <- tail(bits, -6)
if (type == 4) { # literal value
n_groups <- which.min(bits[seq(1, length(bits), 5)])
sub <- head(bits, n_groups * 5)
sub <- sub[(seq_along(sub) - 1) %% 5 > 0]
# literal_value <- binary_to_int(sub)
bits <- tail(bits, -n_groups * 5)
next
}
# Operator mode:
lentype <- bits[1]
bits <- bits[-1]
if (lentype == 0) {
sub_length <- binary_to_int(bits[1:15])
bits <- tail(bits, -15)
sub <- head(bits, sub_length)
acc <- acc + packet_versions(sub, depth + 1)[['acc']]
bits <- tail(bits, -sub_length)
} else {
n_subs <- binary_to_int(bits[1:11])
bits <- tail(bits, -11)
sub_result <- packet_versions(bits, depth + 1, n_subs)
acc <- acc + sub_result[['acc']]
bits <- tail(bits, sub_result[['length']])
}
}
if (depth)
acc <- c(acc = acc, length = length(bits))
acc
}
#' @rdname day16
#' @param bits A vector of bits.
#' @export
packet_decode <- function(bits, depth = 0, rem_subs = Inf) {
acc <- NULL
while (any(bits > 0) & rem_subs > 0) {
rem_subs <- rem_subs - 1
type <- binary_to_int(bits[4:6])
bits <- tail(bits, -6)
op <- c('sum', 'prod', 'min', 'max', 'c', '`>`', '`<`', '`==`')[type + 1]
if (type == 4) { # literal value
n_groups <- which.min(bits[seq(1, length(bits), 5)])
sub <- head(bits, n_groups * 5)
sub <- sub[(seq_along(sub) - 1) %% 5 > 0]
literal_value <- binary_to_int(sub)
acc$expr <- c(acc$expr, literal_value)
bits <- tail(bits, -n_groups * 5)
next
}
# Operator mode:
lentype <- bits[1]
bits <- bits[-1]
if (lentype == 0) {
sub_length <- binary_to_int(bits[1:15])
bits <- tail(bits, -15)
sub <- head(bits, sub_length)
sub_result <- packet_decode(sub, depth + 1)
subexpr <- c(op, sub_result[['expr']])
acc$expr <- c(acc$expr, list(subexpr))
bits <- tail(bits, -sub_length)
} else {
n_subs <- binary_to_int(bits[1:11])
bits <- tail(bits, -11)
sub_result <- packet_decode(bits, depth + 1, n_subs)
subexpr <- c(op, sub_result[['expr']])
acc$expr <- c(acc$expr, list(subexpr))
bits <- tail(bits, sub_result[['length']])
}
}
if (depth)
acc$length <- length(bits)
acc
}
combine_expr <- function(node, eval = FALSE) {
if (length(node) == 1)
return(node)
expr <- sprintf('%s(%s)', node[1], paste(node[-1], collapse = ', '))
if (!eval)
return(expr)
eval(str2expression(expr))
}
#' @rdname day16
#' @param tree A (deeply) nested list, as produced from `packet_decode`.
#' @param eval Logical. Evaluate the final expression?
#' @export
packet_parse <- function(tree, eval = FALSE) {
if (!is.list(tree))
return(combine_expr(tree, eval))
expr <- packet_parse(unlist(lapply(tree, packet_parse, eval), use.names = F))
if (eval & is.character(expr))
return(eval(parse(text = expr)))
expr
}
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