test_that("breaks returns appropriate results", {
df <- rnorm(500, 20, 5)
dt <- breaks(df, 'quantile', nbins=20)
expect_equal(length(dt), 21)
dt <- breaks(df, 'quantile', binwidth=0.5)
expect_equal(length(dt), 3)
expect_equal(names(dt), c('0%','50%','100%'))
dt <- breaks(c(1,2), 'equalInterval', binwidth=0.5)
expect_equal(dt, c(1, 1.5, 2))
dt <- breaks(df, 'sd')
expect_equal(all.equal(dt, c(min(min(df),median(df) - 3*sd(df)),
median(df) - 2*sd(df),
median(df) - sd(df),
median(df),
median(df) + sd(df),
median(df) + 2*sd(df),
max(max(df),median(df) + 3*sd(df))), tolerance=.5), TRUE)
})
test_that("cut_width splits the first inclusive bin for integers where bin width is 1", {
ints <- c(0,1,2,2,3,3,3,4,4,4,4)
expectedBins <- c("[-1,0]","(0,1]","(1,2]","(1,2]","(2,3]","(2,3]","(2,3]","(3,4]","(3,4]","(3,4]","(3,4]")
expect_equal(as.character(cut_width(ints, 1, .5)), expectedBins)
expect_equal(as.character(cut_width(ints,1,boundary=min(ints))), expectedBins)
})
test_that("cut_width splits the last inclusive bin for integers where bin width is 1", {
ints <- c(0,1,2,2,3,3,3,4,4,4,4)
expectedBins <- c("[0,1)","[1,2)","[2,3)","[2,3)","[3,4)","[3,4)","[3,4)","[4,5]","[4,5]","[4,5]","[4,5]")
expect_equal(as.character(cut_width(ints, 1, .5, closed = "left")), expectedBins)
expect_equal(as.character(cut_width(ints,1,boundary=max(ints),closed = "left")), expectedBins)
})
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