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#####################
# internal function #
#####################
#' processMultipleSigSets (internal function)
#'
#' Performs the quadratic programming/exposure prediction for multiple
#' subsets (of size k) of mutational signatures and returns information on the
#' best subset (highest explained variance). This function is used by
#' \code{getBestDecomp4Ksignatures} and \code{addBestSignatureToSubset}.
#'
#' @usage processMultipleSigSets(genome, signatures, sigCombn, k,
#' constrainToMaxContribution=FALSE, tolerance=0.1)
#' @param genome Genome for which to approximate the decomposition.
#' @param signatures The whole set of signatures (from which to choose
#' a subset signatures.
#' @param sigCombn The combinations of subsets of \code{k} signatures to use.
#' Has to be the same format as generated by \code{combn}.
#' @param k Number of signatures to use (subset size).
#' @param constrainToMaxContribution (Optional) [Note: this is experimental
#' and is usually not needed!] If \code{TRUE}, the maximum contribution that
#' can be attributed to a signature will be constraint by the variant feature
#' counts (e.g., specific flanking bases) observed in the individual tumor
#' genome. If, for example, 30\% of all observed variants have a specific
#' feature and 60\% of the variants produced by a mutational process/signature
#' will manifest the feature, then the signature can have contributed up to
#' 0.3/0.6 (=0.5 or 50\%) of the observed variants. The lowest possible
#' contribution over all signature features will be taken as the allowed
#' maximum contribution of the signature. This allowed maximum will
#' additionally be increased by the value specified as \code{tolerance}
#' (see below). For the illustrated example and \code{tolerance}=0.1 a
#' contribution of up to 0.5+0.1 = 0.6 (or 60\%) of the signature would be
#' allowed.
#' @param tolerance (Optional) If \code{constrainToMaxContribution} is
#' \code{TRUE}, the maximum contribution computed for a signature is increased
#' by this value (see above). If the parameter \code{constrainToMaxContribution}
#' is \code{FALSE}, the tolerance value is ignored. Default: 0.1.
#' @return A list object containing: k=number of signatures;
#' explVar=variance explained by these signatures;
#' sigList=list of the signatures;
#' decomposition=decomposition (exposures) obtained with these signatures.
#' @author Rosario M. Piro\cr Politecnico di Milano\cr Maintainer: Rosario
#' M. Piro\cr E-Mail: <rmpiro@@gmail.com> or <rosariomichael.piro@@polimi.it>
#' @references \url{http://rmpiro.net/decompTumor2Sig/}\cr
#' Krueger, Piro (2019) decompTumor2Sig: Identification of mutational
#' signatures active in individual tumors. BMC Bioinformatics
#' 20(Suppl 4):152.\cr
#' @keywords internal
processMultipleSigSets <- function(genome, signatures, sigCombn, k,
constrainToMaxContribution=FALSE,
tolerance=0.1) {
decompTmp <- lapply(sigCombn, function(sigIndices) {
# signatures to be used
sigs <- signatures[sigIndices]
# decompose for these signatures
QPforSig(genome, sigs,
constrainToMaxContribution=constrainToMaxContribution,
tolerance=tolerance)
} )
explVarTmp <- vapply(names(decompTmp), function(sigsNames) {
# signatures to be used
sigs <- signatures[unlist(strsplit(sigsNames, "|", fixed=TRUE))]
# determine the explained variance for this decomposition
computeExplainedVariance(decompTmp[sigsNames], sigs, list(genome))
}, FUN.VALUE=numeric(1) )
names(explVarTmp) <- names(decompTmp)
# which was the best explained variance for this number of signatures?
explVar <- max(explVarTmp)
# which decomposition achieved this explained variance? If multiple do,
# select one at random
if (length(which(explVarTmp == explVar)) > 1) {
explVarIndex <- sample(which(explVarTmp == explVar),1)
} else {
# only on, using sample would lead to wrong behavior!
explVarIndex <- which(explVarTmp == explVar)
}
sigList <-
unlist(strsplit(names(explVarTmp)[explVarIndex], "|", fixed=TRUE))
decomposition <- decompTmp[[explVarIndex]]
names(decomposition) <- sigList
list(k = k,
explVar = explVar,
sigList = sigList,
decomposition = decomposition)
}
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