Assuming the input vector contains a vectorized form of the distance representation of a symmetric matrix, this function creates the corresponding matrix. This is useful when re-forming symmetric matrices that have been vectorized to save storage space.
a numeric vector
value to be put on the diagonal. Recycled if necessary.
The function assumes that
x contains the vectorized form of the distance representation of a
symmetric matrix. In particular,
x must have a length that can be expressed as n*(n-1)/2, with n an
integer. The result of the function is then an n times n matrix.
A symmetric matrix whose lower triangle is given by
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# Create a symmetric matrix m = matrix(c(1:16), 4,4) mat = (m + t(m)); diag(mat) = 0; # Print the matrix mat # Take the lower triangle and vectorize it (in two ways) x1 = mat[lower.tri(mat)] x2 = as.vector(as.dist(mat)) all.equal(x1, x2) # The vectors are equal # Turn the vectors back into matrices new.mat = lowerTri2matrix(x1, diag = 0); # Did we get back the same matrix? all.equal(mat, new.mat)
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