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## Copyright (C) 2000 Paul Kienzle
##
## This program is free software; you can redistribute it and/or modify
## it under the terms of the GNU General Public License as published by
## the Free Software Foundation; either version 2 of the License, or
## (at your option) any later version.
##
## This program is distributed in the hope that it will be useful,
## but WITHOUT ANY WARRANTY; without even the implied warranty of
## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
## GNU General Public License for more details.
##
## You should have received a copy of the GNU General Public License
## along with this program; if not, write to the Free Software
## Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
## usage: b = fir2(n, f, m [, grid_n [, ramp_n]] [, window])
##
## Produce an FIR filter of order n with arbitrary frequency response,
## returning the n+1 filter coefficients in b.
##
## n: order of the filter (1 less than the length of the filter)
## f: frequency at band edges
## f is a vector of nondecreasing elements in [0,1]
## the first element must be 0 and the last element must be 1
## if elements are identical, it indicates a jump in freq. response
## m: magnitude at band edges
## m is a vector of length(f)
## grid_n: length of ideal frequency response function
## defaults to 512, should be a power of 2 bigger than n
## ramp_n: transition width for jumps in filter response
## defaults to grid_n/20; a wider ramp gives wider transitions
## but has better stopband characteristics.
## window: smoothing window
## defaults to hamming(n+1) row vector
## returned filter is the same shape as the smoothing window
##
## To apply the filter, use the return vector b:
## y=filter(b,1,x)
## Note that plot(f,m) shows target response.
##
## Example:
## f=[0, 0.3, 0.3, 0.6, 0.6, 1]; m=[0, 0, 1, 1/2, 0, 0]
## [h, w] = freqz(fir2(100,f,m))
## plot(f,m,';target response;',w/pi,abs(h),';filter response;')
## Feb 27, 2000 PAK
## use ramping on any transition less than ramp_n units
## use 2^nextpow2(n+1) for expanded grid size if grid is too small
## 2001-01-30 PAK
## set default ramp length to grid_n/20 (i.e., pi/20 radians)
## use interp1 to interpolate the grid points
## better(?) handling of 0 and pi frequency points.
## added some demos
fir2 <- function(n, f, m, grid_n = 512, ramp_n = grid_n/20, window = hamming(n+1)) {
## verify frequency and magnitude vectors are reasonable
t = length(f)
if (t<2 || f[1]!=0 || f[t]!=1 || any(diff(f)<0))
stop("frequency must be nondecreasing starting from 0 and ending at 1")
if (t != length(m))
stop("frequency and magnitude vectors must be the same length")
## find the grid spacing and ramp width
if (length(grid_n)>1 || length(ramp_n)>1)
stop("grid_n and ramp_n must be integers")
## find the window parameter, or default to hamming
# if (!is.double(window))
# window = feval(window, n+1)
if (length(window) != n+1)
stop("window must be of length n+1")
## make sure grid is big enough for the window
if (2*grid_n < n+1)
grid_n = 2^ceiling(log2(abs(n+1)))
## Apply ramps to discontinuities
if (ramp_n > 0) {
## remember original frequency points prior to applying ramps
basef = f
basem = m
## separate identical frequencies, but keep the midpoint
idx = which(diff(f) == 0)
f[idx] = f[idx] - ramp_n/grid_n/2
f[idx+1] = f[idx+1] + ramp_n/grid_n/2
f = c(f, basef[idx])
## make sure the grid points stay monotonic in [0,1]
f[f<0] = 0
f[f>1] = 1
f = sort(unique(c(f, basef[idx])))
## preserve window shape even though f may have changed
m = approx(basef, basem, f, ties="ordered")$y
}
## interpolate between grid points
grid = approx(f,m,seq(0, 1, length = grid_n+1), ties = "ordered")$y
## Transform frequency response into time response and
## center the response about n/2, truncating the excess
if((n %% 2) == 0) {
b = fft(c(grid, grid[seq(grid_n, 2, by = -1)]), inverse = TRUE)
b = b / length(b)
mid = (n+1)/2
b = Re(c(b[(2*grid_n-floor(mid)+1):(2*grid_n)], b[1:ceiling(mid)]))
} else {
b = fft(c(grid, rep(0, grid_n*2), grid[seq(grid_n, 2, by = -1)]), inverse = TRUE)
b = b / length(b)
b = 2 * Re(c(b[seq(length(b)-n+1, length(b), by=2)], b[seq(2, n+2, by=2)]))
}
## Multiplication in the time domain is convolution in frequency,
## so multiply by our window now to smooth the frequency response.
b = b * window
Ma(b)
}
#!demo
#! f=[0, 0.3, 0.3, 0.6, 0.6, 1]; m=[0, 0, 1, 1/2, 0, 0]
#! [h, w] = freqz(fir2(100,f,m))
#! subplot(121)
#! plot(f,m,';target response;',w/pi,abs(h),';filter response;')
#! subplot(122)
#! plot(f,20*log10(m+1e-5),';target response (dB);',...
#! w/pi,20*log10(abs(h)),';filter response (dB);')
#! oneplot
#!demo
#! f=[0, 0.3, 0.3, 0.6, 0.6, 1]; m=[0, 0, 1, 1/2, 0, 0]
#! plot(f,20*log10(m+1e-5),';target response;')
#! hold on
#! [h, w] = freqz(fir2(50,f,m,512,0))
#! plot(w/pi,20*log10(abs(h)),';filter response (ramp=0);')
#! [h, w] = freqz(fir2(50,f,m,512,25.6))
#! plot(w/pi,20*log10(abs(h)),';filter response (ramp=pi/20 rad);')
#! [h, w] = freqz(fir2(50,f,m,512,51.2))
#! plot(w/pi,20*log10(abs(h)),';filter response (ramp=pi/10 rad);')
#! hold off
#!demo
#! % Classical Jakes spectrum
#! % X represents the normalized frequency from 0
#! % to the maximum Doppler frequency
#! asymptote = 2/3
#! X = linspace(0,asymptote-0.0001,200)
#! Y = (1 - (X./asymptote).^2).^(-1/4)
#!
#! % The target frequency response is 0 after the asymptote
#! X = [X, asymptote, 1]
#! Y = [Y, 0, 0]
#!
#! title('Theoretical/Synthesized CLASS spectrum')
#! xlabel('Normalized frequency (Fs=2)')
#! ylabel('Magnitude')
#!
#! plot(X,Y,'b;Target spectrum;')
#! hold on
#! [H,F]=freqz(fir2(20, X, Y))
#! plot(F/pi,abs(H),'c;Synthesized spectrum (n=20);')
#! [H,F]=freqz(fir2(50, X, Y))
#! plot(F/pi,abs(H),'r;Synthesized spectrum (n=50);')
#! [H,F]=freqz(fir2(200, X, Y))
#! plot(F/pi,abs(H),'g;Synthesized spectrum (n=200);')
#! hold off
#! xlabel(''); ylabel(''); title('')
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