tests/overlap.R

#
# Make sure that useless intervals do not cause issues, i.e., any that do
#  not overlap at least one event time
#
library(survival)
test2 <- data.frame(time1 =c(1, 2, 5, 2, 1, 7, 3, 4, 8, 8, 3),
                    time2 =c(2, 3, 6, 7, 8, 9, 9, 9,14,17, 5),
                    event =c(1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0),
                    x     =c(1, 0, 0, 1, 0, 1, 1, 1, 0, 0, 500) )

# The data set is the same as book3.R, except for the wild observation
#  with x=500 whose time interval of (4,5) overlaps no events.

fit1 <- coxph(Surv(time1, time2, event) ~ x, test2, subset=(x<100))
fit2 <- coxph(Surv(time1, time2, event) ~ x, test2)

ii <- match(c("coefficients", "var", "loglik", "score", "iter", 
              "wald.test", "concordance"), names(fit1))
all.equal(fit1[ii], fit2[ii])
all.equal(c(fit1$residuals,0), fit2$residuals, check.attributes=FALSE)

# The mean differs condiderably, and so to the linear predictors

# Now the same with a penalized model
fit3 <- coxph(Surv(time1, time2, event) ~ ridge(x, theta=.1), test2,
              subset= (x< 100))
fit4 <-  coxph(Surv(time1, time2, event) ~ ridge(x, theta=.1), test2)
fit5 <- coxph(Surv(time1,time2, event) ~ x, test2,
              iter=0, init=fit4$coef)

all.equal(fit3[ii], fit4[ii])
all.equal(c(fit3$residuals,0),  fit4$residuals, check.attributes=FALSE)
all.equal(fit4$residuals, fit5$residuals)

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survival documentation built on Aug. 24, 2021, 5:06 p.m.