View source: R/branches_attr_by.R
branches_attr_by_labels | R Documentation |
The user supplies a dend, labels, and type of condition (all/any), and TF_values And the function returns a dendrogram with branches col/lwd/lty accordingly
branches_attr_by_labels(
dend,
labels,
TF_values = c(2, Inf),
attr = c("col", "lwd", "lty"),
type = c("all", "any"),
...
)
dend |
a dendrogram dend |
labels |
a character vector of labels from the tree |
TF_values |
a two dimensional vector with the TF_values to use in case a branch fulfills the condition (TRUE) and in the case that it does not (FALSE). Defaults are 2/Inf for col, lwd and lty. (so it will insert the first value, and will not change all the FALSE cases) |
attr |
a character with one of the following values: col/lwd/lty |
type |
a character vector of either "all" or "any", indicating which of the branches should be painted: ones that all of their labels belong to the supplied labels, or also ones that even some of their labels are included in the labels vector. |
... |
ignored. |
A dendrogram with modified branches (col/lwd/lty).
noded_with_condition, get_leaves_attr, nnodes, nleaves
## Not run:
library(dendextend)
set.seed(23235)
ss <- sample(1:150, 10)
# Getting the dend dend
dend <- iris[ss, -5] %>%
dist() %>%
hclust() %>%
as.dendrogram()
dend %>% plot()
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29")) %>%
plot()
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29"), "all") %>%
plot() # the same as above
dend %>%
branches_attr_by_labels(c("123", "126", "23", "29"), "any") %>%
plot()
dend %>%
branches_attr_by_labels(
c("123", "126", "23", "29"),
"any", "col", c("blue", "red")
) %>%
plot()
dend %>%
branches_attr_by_labels(
c("123", "126", "23", "29"),
"any", "lwd", c(4, 1)
) %>%
plot()
dend %>%
branches_attr_by_labels(
c("123", "126", "23", "29"),
"any", "lty", c(2, 1)
) %>%
plot()
## End(Not run)
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