View source: R/exponentiate.fd.R
exponentiate.fd | R Documentation |
Exponentiate a functional data object where feasible.
## S3 method for class 'fd'
e1 ^ e2
exponentiate.fd(e1, e2, tolint=.Machine$double.eps^0.75,
basisobj=e1$basis,
tolfd=sqrt(.Machine$double.eps)*
sqrt(sum(e1$coefs^2)+.Machine$double.eps)^abs(e2),
maxbasis=NULL, npoints=NULL)
e1 |
object of class 'fd'. |
e2 |
a numeric vector of length 1. |
basisobj |
reference basis |
tolint |
if abs(e2-round(e2))<tolint, we assume e2 is an integer. This simplifies the algorithm. |
tolfd |
the maximum error allowed in the difference between the direct
computation |
maxbasis |
The maximum number of basis functions in growing
|
npoints |
The number of points at which to compute |
If e1 has a B-spline basis, this uses the B-spline algorithm.
Otherwise it throws an error unless it finds one of the following special cases:
e2 = 0
Return an fd
object with a constant basis that is
everywhere 1
e2 is a positive integer to within tolint Multiply e1 by itself e2 times
e2 is positive and e1 has a Fourier basis e120 <- e1^floor(e2)
outBasis <- e120$basis
rng <- outBasis$rangeval
Time <- seq(rng[1], rng[2], npoints)
e1.2 <- predict(e1, Time)^e2
fd1.2 <- smooth.basis(Time, e1.2, outBasis)$
d1.2 <- (e1.2 - predict(fd1.2, Time))
if(all(abs(d1.2)<tolfd))return(fd1.2)
Else if(outBasis$nbasis<maxbasis) increase the size of outBasis and try again.
Else write a warning with the max(abs(d1.2)) and return fd1.2.
A function data object approximating the desired power.
arithmetic.fd
basisfd
,
basisfd.product
##
## sin^2
##
basis3 <- create.fourier.basis(nbasis=3)
oldpar <- par(no.readonly=TRUE)
plot(basis3)
# max = sqrt(2), so
# integral of the square of each basis function (from 0 to 1) is 1
integrate(function(x)sin(2*pi*x)^2, 0, 1) # = 0.5
# sin(theta)
fdsin <- fd(c(0,sqrt(0.5),0), basis3)
plot(fdsin)
fdsin2 <- fdsin^2
# check
fdsinsin <- fdsin*fdsin
# sin^2(pi*time) = 0.5*(1-cos(2*pi*theta) basic trig identity
plot(fdsinsin) # good
all.equal(fdsin2, fdsinsin)
par(oldpar)
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