Nothing
Code
clustering_cv(dat1)
Condition
Error in `clustering_cv()`:
! `vars` is required and must contain at least one variable in `data`.
Code
clustering_cv(iris, Sepal.Length, v = -500)
Condition
Error in `clustering_cv()`:
! `v` must be a whole number larger than or equal to 2, not the number -500.
Code
clustering_cv(iris, Sepal.Length, v = 500)
Condition
Error in `clustering_cv()`:
! The number of rows is less than `v` = 500.
Code
clustering_cv(iris, Sepal.Length, cluster_function = "not an option")
Condition
Error in `clustering_cv()`:
! `cluster_function` must be one of "kmeans" or "hclust", not "not an option".
Code
clustering_cv(Orange, v = 1, vars = "Tree")
Condition
Error in `clustering_cv()`:
! `v` must be a whole number larger than or equal to 2, not the number 1.
Code
clustering_cv(Orange, repeats = 0)
Condition
Error in `clustering_cv()`:
! `repeats` must be a whole number larger than or equal to 1, not the number 0.
Code
clustering_cv(Orange, repeats = NULL)
Condition
Error in `clustering_cv()`:
! `repeats` must be a whole number, not `NULL`.
Code
clustering_cv(mtcars, mpg, v = nrow(mtcars))
Condition
Error in `clustering_cv()`:
! Leave-one-out cross-validation is not supported by this function.
x You set `v` to `nrow(data)`, which would result in a leave-one-out cross-validation.
i Use `loo_cv()` in this case.
Code
clustering_cv(dat1, c, v = 2)
Output
# 2-cluster cross-validation
# A tibble: 2 x 2
splits id
<list> <chr>
1 <split [5/15]> Fold1
2 <split [15/5]> Fold2
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