Nothing
"scores.default" <-
function (x, choices, display = c("sites", "species"), ...)
{
display <- match.arg(display)
att <- names(x)
if (is.data.frame(x) && all(sapply(x, is.numeric)))
x <- as.matrix(x)
if (is.list(x) && display == "sites") {
if ("points" %in% att)
X <- x$points
else if ("rproj" %in% att)
X <- x$rproj
else if ("x" %in% att)
X <- x$x
else if ("scores" %in% att)
X <- x$scores
else if ("sites" %in% att)
X <- x$sites
else if("li" %in% att)
X <- x$li
else if("l1" %in% att)
X <- x$l1
else stop("Can't find scores")
}
else if (is.list(x) && display == "species") {
if ("species" %in% att)
X <- x$species
else if ("cproj" %in% att)
X <- x$cproj
else if ("rotation" %in% att)
X <- x$rotation
else if ("loadings" %in% att)
X <- x$loadings
else if ("co" %in% att)
X <- x$co
else if ("c1" %in% att)
X <- x$c1
else stop("Can't find scores")
}
else if (is.numeric(x)) {
X <- as.matrix(x)
## as.matrix() changes a score vector to 1-col matrix: this is
## a hack which may fail sometimes (but probably less often
## than without this hack):
## Removed this hack after an issue raised by
## vanderleidebastiani in github. He was worried for getting
## an error when 'choices' were not given with genuinely 1-dim
## (1-col) results. At a second look, it seems that this hack
## will fail both with missing 'choices', and also often with
## 'choices' given because 'choices' are only applied later,
## so that nrow(X) > length(choices). Only vectors (dim arg
## missing) should fail here. Let's see...
##if (ncol(X) == 1 && nrow(X) == length(choices))
## X <- t(X)
}
if (is.null(rownames(X))) {
root <- substr(display, 1, 4)
rownames(X) <- paste(root, 1:nrow(X), sep = "")
}
if (is.null(colnames(X)))
colnames(X) <- paste("Dim", 1:ncol(X), sep = "")
if (!missing(choices)) {
choices <- choices[choices <= ncol(X)]
X <- X[, choices, drop = FALSE]
}
X <- as.matrix(X)
X
}
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