View source: R/noded_with_condition.R
which_node | R Documentation |
This function identifies which edge(s) in a tree has group of labels ("tips") in common. By default it only returns the edge (node) with the heighest id.
which_node(dend, labels, max_id = TRUE, ...)
dend |
a dendrogram dend |
labels |
a character vector of labels from the tree |
max_id |
logical (TRUE) - if to return only the max id |
... |
ignored. |
An integer with the id(s) of the nodes which includes all of the labels.
noded_with_condition, branches_attr_by_clusters, nnodes, branches_attr_by_labels, get_nodes_attr which.edge
dend <- iris[1:10, -5] %>%
dist() %>%
hclust() %>%
as.dendrogram() %>%
set("labels", 1:10)
dend %>% plot()
which_node(dend, c(1, 2), max_id = FALSE)
which_node(dend, c(2, 3), max_id = FALSE)
which_node(dend, c(2, 3))
dend %>% plot()
the_h <- get_nodes_attr(dend, "height", which_node(dend, c(4, 6)))
the_h
abline(h = the_h, lty = 2, col = 2)
get_nodes_attr(dend, "height", which_node(dend, c(4, 6)))
get_nodes_attr(dend, "members", which_node(dend, c(4, 6)))
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