AgivenF | R Documentation |
Compute A given F
AgivenF(
F,
n,
i,
frequency = c("annual", "semiannual", "quarter", "bimonth", "month", "daily")
)
AF(
F,
n,
i,
frequency = c("annual", "semiannual", "quarter", "bimonth", "month", "daily")
)
F |
numeric vector that contains the future value(s) |
n |
numeric vector that contains the period value(s) |
i |
numeric vector that contains the interest rate(s) as a percent |
frequency |
character vector that contains the frequency used to obtain the number of periods [annual (1), semiannual (2), quarter (4), bimonth (6), month (12), daily (365)] |
A is expressed as
A = F\left[\frac{i}{\left(1 + i\right)^n - 1}\right]
the "uniform series amount (occurs at the end of each interest period)"
the "future equivalent"
the "effective interest rate per interest period"
the "number of interest periods"
AgivenF numeric vector that contains the annual value(s) rounded to 2 decimal places
AF data.frame of both n (0 to n) and the resulting annual values rounded to 2 decimal places
Irucka Embry
William G. Sullivan, Elin M. Wicks, and C. Patrick Koelling, Engineering Economy, Fourteenth Edition, Upper Saddle River, New Jersey: Pearson/Prentice Hall, 2009, page 135-136, 142, 164.
library(iemisc)
# Example for equation 4-12 from the Reference text (page 135-136)
AgivenF(309*10^6, 60, 0.5, "month")
# the interest rate is 0.5\% per month and n is 60 months
# "$4.4187 million per month" is the answer
AF(309*10^6, 60, 0.5, "annual")
# the interest rate is 0.5\% per month and n is 60 months
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