riem.pdist2: Compute Pairwise Distances for Two Sets of Data

In Riemann: Learning with Data on Riemannian Manifolds

Compute Pairwise Distances for Two Sets of Data

Description

Given M observations X_1, X_2, …, X_M \in \mathcal{M} and N observations Y_1, Y_2, …, Y_N \in \mathcal{M}, compute pairwise distances between two sets' elements.

Usage

riem.pdist2(riemobj1, riemobj2, geometry = c("intrinsic", "extrinsic"))

Arguments

riemobj1	a S3 "riemdata" class for M manifold-valued data.
riemobj2	a S3 "riemdata" class for N manifold-valued data.
geometry	(case-insensitive) name of geometry; either geodesic ("intrinsic") or embedded ("extrinsic") geometry.

Value

an (M\times N) matrix of distances.

Examples

#-------------------------------------------------------------------
#          Example on Sphere : a dataset with two types
#
#  group1 : 10 perturbed data points near (0,0,1) on S^2 in R^3
#  group2 : 10 perturbed data points near (1,0,0) on S^2 in R^3
#           10 perturbed data points near (0,1,0) on S^2 in R^3
#           10 perturbed data points near (0,0,1) on S^2 in R^3
#-------------------------------------------------------------------
## GENERATE DATA
mydata1 = list()
mydata2 = list()
for (i in 1:10){
  tgt = c(stats::rnorm(2, sd=0.1), 1)
  mydata1[[i]] = tgt/sqrt(sum(tgt^2))
}
for (i in 1:10){
  tgt = c(1, stats::rnorm(2, sd=0.1))
  mydata2[[i]] = tgt/sqrt(sum(tgt^2))
}
for (i in 11:20){
  tgt = c(rnorm(1,sd=0.1),1,rnorm(1,sd=0.1))
  mydata2[[i]] = tgt/sqrt(sum(tgt^2))
}
for (i in 21:30){
  tgt = c(stats::rnorm(2, sd=0.1), 1)
  mydata2[[i]] = tgt/sqrt(sum(tgt^2))
}
myriem1 = wrap.sphere(mydata1)
myriem2 = wrap.sphere(mydata2)

## COMPARE TWO DISTANCES
dint = riem.pdist2(myriem1, myriem2, geometry="intrinsic")
dext = riem.pdist2(myriem1, myriem2, geometry="extrinsic")

## VISUALIZE
opar = par(no.readonly=TRUE)
par(mfrow=c(1,2))
image(dint[nrow(dint):1,], main="intrinsic", axes=FALSE)
image(dext[nrow(dext):1,], main="extrinsic", axes=FALSE)
par(opar)

Riemann documentation built on March 18, 2022, 7:55 p.m.