tests/testthat/test-HRD_and_MHRD.R

In roahd: Robust Analysis of High Dimensional Data

test_that("hrd() & mhrd() work as expected", {
  time_grid <- seq(0, 1, length.out = 1e2)

  D <- matrix(c(
    sin(2 * pi * time_grid) + 10,
    sin(2 * pi * time_grid) + 9,
    sin(2 * pi * time_grid) + 8,
    sin(2 * pi * time_grid) + 7,
    sin(2 * pi * time_grid) + 6,
    sin(2 * pi * time_grid) + 5,
    sin(2 * pi * time_grid) + 4,
    sin(2 * pi * time_grid) + 3,
    sin(2 * pi * time_grid) + 2,
    sin(2 * pi * time_grid) + 1,
    sin(2 * pi * time_grid) + 0,
    sin(2 * pi * time_grid) - 1,
    sin(2 * pi * time_grid) - 2,
    sin(2 * pi * time_grid) - 3,
    sin(2 * pi * time_grid) - 4,
    sin(2 * pi * time_grid) - 5,
    sin(2 * pi * time_grid) - 6,
    sin(2 * pi * time_grid) - 7,
    sin(2 * pi * time_grid) - 8,
    sin(2 * pi * time_grid) - 9,
    sin(2 * pi * time_grid) - 10),
    nrow = 21, ncol = length(time_grid), byrow = TRUE
  )

  N <- nrow(D)
  id_vector <- 1:N

  expect_equal(HRD(D), mapply(min, id_vector / N, (N - id_vector + 1) / N))
  expect_equal(MHRD(D), mapply(min, id_vector / N, (N - id_vector + 1) / N))
})

test_that("hrd() works on test by James Long (TAMU)", {
  yints <- c( 1.27, .927, 1/2, .217, 0)
  slopes <- c(-1, -1, 0, 1, 1)
  time_grid <- (0:100) / 100

  Data <- matrix(0, nrow = length(yints), ncol = length(time_grid))
  for (i in 1:length(yints))
    Data[i, ] <- yints[i] + time_grid * slopes[i]

  expect_equal(HRD(Data), rep(0.2, 5))
})