| ls.str | R Documentation |
ls.str and lsf.str are variations of ls
applying str() to each matched name: see section Value.
ls.str(pos = -1, name, envir, all.names = FALSE,
pattern, mode = "any")
lsf.str(pos = -1, envir, ...)
## S3 method for class 'ls_str'
print(x, max.level = 1, give.attr = FALSE, ...,
digits = max(1, getOption("str")$digits.d))
pos |
integer indicating |
name |
optional name indicating |
envir |
environment to use, see |
all.names |
logical indicating if names which begin with a
|
pattern |
a regular expression passed to |
max.level |
maximal level of nesting which is applied for displaying nested structures, e.g., a list containing sub lists. Default 1: Display only the first nested level. |
give.attr |
logical; if |
mode |
character specifying the |
x |
an object of class |
... |
further arguments to pass. |
digits |
the number of significant digits to use for printing. |
ls.str and lsf.str return an object of class
"ls_str", basically the character vector of matching names
(functions only for lsf.str), similarly to
ls, with a print() method that calls str()
on each object.
Martin Maechler
str, summary, args.
require(stats)
lsf.str() #- how do the functions look like which I am using?
ls.str(mode = "list") #- what are the structured objects I have defined?
## create a few objects
example(glm, echo = FALSE)
ll <- as.list(LETTERS)
print(ls.str(), max.level = 0)# don't show details
## which base functions have "file" in their name ?
lsf.str(pos = length(search()), pattern = "file")
## demonstrating that ls.str() works inside functions
## ["browser/debug mode"]:
tt <- function(x, y = 1) { aa <- 7; r <- x + y; ls.str() }
(nms <- sapply(strsplit(capture.output(tt(2))," *: *"), `[`, 1))
stopifnot(nms == c("aa", "r","x","y"))
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